if 4sina = 3cosa, then sec sq. q / 4(1-tan sq. q)
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Answer:
25/28
Step-by-step explanation:
4 SinA = 3 CosA
SinA/CosA = 3/4
TanA = 3/4
Sec^2A = 1 + Tan^2A = 1 + (3/4 ) ^2
= 1 + 9/16 = 25/16
1-Tan^2A = 1-9/16 = 7/16
Sec^2A / 4 ( 1 - Tan^2A ) = 25/28
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