Question

If 4sinØ = 3cosØ, find the value of cosØ
[Please answer me as soon as possible its an earnest request]

Answer 1

The required answer is 4/5

Answer 2

sin theta = P/H
=> 4sin theta = 4P/H
cos theta = B/H
=> 3cos theta = 3B/H

According to question,
4P/H = 3B/H
=> 4P = 3B
=>P/B = 3/4
Let the perpendicular P be 3x and base B be 4x
Then, By Pythagoras theorem,
Hypotenuse H = 5x

Therefore, cos theta = Base/Hypotenuse
=> cos theta = 4x/5x = 4/5

Hence, the value of cos theta = 4/5

Hope it helps,
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