if 4tan∅=3 evaluate 4sin∅ - cos∅+1/4sin∅+cos∅+1
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Sidi du du du du St St St at BJ ml no
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Answer:
Note : I have done the solution in detail
according to question :-
if 4tanΦ = 3
then tan Φ = 3/4
now tan Φ = P/b
so P/b = 3/4
P (perpendicular) = 3
B (base) = 4
now using Pythagoras theorem :-
hypotenuse ^2 = perpendicular ^2 + base ^2
hypotenuse ^2 = 3^2 + 4^2
hypotenuse ^2 = 9+16
hypotenuse ^2 = 25
hypotenuse = √25 = 5
now sin Φ = P/h = 3/5
cos Φ = b/h = 4/5
now evaluate :-
putting values in question :
4sin Φ - cos Φ +1 / 4sin Φ + cos Φ + 1
4*3/5 - 4/5 + 1 / 4*3/5 + 4/5 + 1
12/5 - 4/5 + 1 / 12/5 + 4/5 + 1
12-4-5 / 5 whole divided by 12+4+5 / 5
(3/5) / (21/5 )
doing reciprocal :-
3/5 * 5/21 = 1/7 Answer
hope you understand plz thank my answer
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