if 4tan A = 3 find the value of (5 cosec A + 10 sec A)
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Answer:
Hope this helps you
Step-by-step explanation:
cos (theta) = 3/5
So, sin (theta) = [sqrt (1 - 9/25)] = 4/5
Then, cosec (theta) = 1/sin (theta) = 5/4
tan (theta) = sin (theta)/cos (theta) = 4/3
And, then, cot (theta) = 1/tan (theta) = 3/4
sec (theta) = 1/cos (theta) = 5/3
Now, [5*cosec (theta) - 4*tan (theta)] /[sec (theta) + cot (theta)] = (5*5/4 - 4*4/3)/(5/3+3/4) = (25/4 + 16/3)/(5/3 + 3/4) = 139/29. (answer)
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