If 4tan A=5, find the value of sin B, cos B, tan B?
Answers
Answered by
0
Answer:
sin b =4/(41)1/2
cos b=4/(41)1/2
tan b=4/5
Answered by
0
Given : 4tan A=5
To Find : value of sin B, cos B, tan B?
Solution:
Assuming right angle triangle with right angle at C
4tan A=5
=> tan A = 5/4
=> tan A = BC/AC
BC/AC = 5/4
BC = 5k
then AC = 4k
AB = √(4k)² + (5k)² = k√41
Sin B = AC/AB = 4k / k√41 = 4/√41
Cos B = BC/ AB = 5k / k√41 = 5/√41
Tan B = AC/BC = 4/5
Learn More:
if sec A+tan A =5 then show that cos A-sinA= 7/13 - Brainly.in
https://brainly.in/question/13210114
If tan theta =4/5,find the value of cos theta -sin theta /cos theta +sin ...
https://brainly.in/question/4217885
Similar questions