if 4tan theta = 3, evalute (4sin theta - cos theta+1/4sin theta + cos theta - 1)
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I hope you can understand this:
tanθ=3/4
Pythagoras Theorem:
hypotenuse=√(3²+4²)=√(9+16)=√(25)=5
(4sinθ-cosθ+1)/(4sinθ+cosθ-1)
=[(4•3/5)-(4/5)+1]/[(4•3/5)+(4/5)-1]
=[(12/5)-(4/5)+1]/[(12/5)+(4/5)-1]
=[(12-4+5)/5]/[(12+4-5)/5]
=(13/5)/(11/5)
=(13/5)•(5/11)
=13/11
tanθ=3/4
Pythagoras Theorem:
hypotenuse=√(3²+4²)=√(9+16)=√(25)=5
(4sinθ-cosθ+1)/(4sinθ+cosθ-1)
=[(4•3/5)-(4/5)+1]/[(4•3/5)+(4/5)-1]
=[(12/5)-(4/5)+1]/[(12/5)+(4/5)-1]
=[(12-4+5)/5]/[(12+4-5)/5]
=(13/5)/(11/5)
=(13/5)•(5/11)
=13/11
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