if 4tanA=3, evaluate (1+sinA)(1-sinA)/(1+cosA)(1-cosA)?
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Given,
4 tan = 3
∴ tan = 3/4
As we know,
Tan = Perpendicular / base
Tan = 3/4
Now,
Hypotenuse = √3² + 4² = √9+16 = √25 = 5
4 tan = 3
∴ tan = 3/4
As we know,
Tan = Perpendicular / base
Tan = 3/4
Now,
Hypotenuse = √3² + 4² = √9+16 = √25 = 5
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