Question

If 4tanA=5 find 3sinA-4cosA\3sinA+cosA

Answer 1

tanA = 5/4

3sinA-4cosA/3sinA+cosA

= cosA(3tanA-4)/cosA(3tanA+1)

= 3(5/4)-4 / 3(5/4)+1

= 15/4 -4 / 15/4 +1

= 15-16/15+4

= -1/19

Hope it helps u :-)