if 4th and 7th are the 2 and 3 terms of an A.P respectively then the first term
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Answered by
1
Answer:
As given:
4th term=2
7th tem=3
let 1st term = a
& common difference=d
hence
a+3d =2>>>>>eq1
& a+6d=3>>>>eq2
solving both eauation
(eq1*2)-(eq2)
we find first term
a= 1
Hope it'll help you.
Answered by
2
Answer:
The First term is 1
Step-by-step explanation:
2nd term = 4
3rd term = 7
d = 7-4 = 3
∴ 1st term = 4-3 = 1
hope this helps
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