if 4th term of an arithmetic progression is 15 ,15th term is -29, find 10th term
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a4 = 15
a+3d = 15
a= 15-3d
a15 = -29
a+14d = -29
15-3d+14d = -29
11d = -29-15
d = -44/11 = -4
a = 15+12 = 27
a10 = 27+9(-4)
a10 = 27-36
a10 = -9
Mark brainliest if you understand:-)
a+3d = 15
a= 15-3d
a15 = -29
a+14d = -29
15-3d+14d = -29
11d = -29-15
d = -44/11 = -4
a = 15+12 = 27
a10 = 27+9(-4)
a10 = 27-36
a10 = -9
Mark brainliest if you understand:-)
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