Question

if 4to the power n+1*2to the power n-8 together power n/2to the power 3m =3/8 ,prove that n+1=m
${4}^{n + 1} \times {2}^{n} - {8}^{n} \div {2}^{3m} = 3 \div 2 \: prove \: that \: n + 1 = m$
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Answer 1

Answer:

Step-by-step explanation:

4^(n+1)*2^n-8^n / 2^3m=3/8

2^[2*(n+1)]*2^n - (2³)^n/2^3m=3/2^3

2^(2n+2)*2^n - 2^3n /2^3m=3/2^3

2^(3n+2) - 2^3n / 2^3m  =3/2^3

2^3n(2^2-1)/2^3m=3/2^3

2^(3n-3m)(4-1)=3*2^-3

3*2^(3n-3m)=3*2^-3

2^(3n-3m)=2^-3

3n-3m=-3

n-m=-1

Hence n+1=m= RHS