if 4x^2-12x+k is a perfect square,find the numerical value of k
Answers
Answered by
102
Hi there!
According to given condtn. :-
4x² - 12x + k = (a - b)² = a² - 2ab + b²
Here,
♦
a² = 4
[ Squaring botg sides. ]
a = √4 = 2
♦
2ab = -12
2(2)b = -12
b = -12 / 4
b = 3
Finally,
♦ b² = k
(3)² = k
k = 9
Hence, The required answer is :-
Numerical value of k = 9
Hope it helps! :)
According to given condtn. :-
4x² - 12x + k = (a - b)² = a² - 2ab + b²
Here,
♦
a² = 4
[ Squaring botg sides. ]
a = √4 = 2
♦
2ab = -12
2(2)b = -12
b = -12 / 4
b = 3
Finally,
♦ b² = k
(3)² = k
k = 9
Hence, The required answer is :-
Numerical value of k = 9
Hope it helps! :)
Answered by
60
Answer :
Now,
4 x² - 12 x + k
= ( 2 x )² - ( 2 × 2 x × 3 ) + 3² - 3² + k
= ( 2 x - 3 )² + ( k - 9 ), since 3² = 9
Thus, the given polynomial be a perfect square is
k - 9 = 0
i.e., k = 9
Therefore, the numerical value of k is 9.
#MarkAsBrainliest
Now,
4 x² - 12 x + k
= ( 2 x )² - ( 2 × 2 x × 3 ) + 3² - 3² + k
= ( 2 x - 3 )² + ( k - 9 ), since 3² = 9
Thus, the given polynomial be a perfect square is
k - 9 = 0
i.e., k = 9
Therefore, the numerical value of k is 9.
#MarkAsBrainliest
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