If 4x^2-1is a factor of 4x^4-12x^3+ax^2+3x-b then find the values of a and b
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Answered by
6
Answer:
a= -1 b= 0
Step-by-step explanation:
a/q 4x^2-1 is a factor of f(x)= 4x^4-12x^3+ax^2+3x-b
=> finding roots of 4x^2-1
=>(2x)^2=1
=>x=+1/2,-1/2
=>using factor theorem
=>f(+1/2)=4×(1/2)^4-12×(1/2)^3+a×(1/2)^2+3×1/2-b=0
=>on solving we get a-4b+1=0. eq 1
now on solving f(-1/2) we get a-4b+1=0
hit and trial
We get a= -1 and b=0 as answer
Answered by
0
Answer:
a=-1 and B=0 is the answer of this question
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