Math, asked by arhamanz152, 10 months ago

If 4x^2 - 2x + 1 = 0 , Then x = ?

Answers

Answered by Anonymous
1

QUESTION:

If 4x^2 - 2x + 1 = 0 , Then x = ?

ANSWER:

Quadratic equation is in the form of

a {x}^{2}  + bx + c = 0

STEP 1:

Split the middle term in such a way that it's sum equal to b i.e -2 and product equal to a ×c that is 4×1 = 4.

4 {x}^{2}  - 2x - 2x + 1

STEP 2 :

Taking common factor.

2x(2x - 1)  - 1(2x - 1)

so,

factors are

(2x - 1)(2x - 1)

now,

2x - 1 = 0 \\ 2x = 1 \\ x =  \frac{1}{2}

FINAL ANSWER :

x =  \frac{1}{2}

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Answered by divyamyindia271
0

Answer:

4 {x}^{2}  - 2x + 1 = 0 \\ x =  \frac{ - b \frac{ + }{ - } \sqrt{ {b}^{2} } - 4ac  }{2a}  \\ x =  \frac{ - ( - 2) \frac{ + }{ - } \sqrt{4 - 4 \times 4 \times 1}  }{2a}  \\ x =  \frac{2 \frac{ + }{ - }  \sqrt{4 - 16} }{2 \times 4}  \\ x =  \frac{2 \frac{ + }{ - }  \sqrt{ - 12} }{8}  \\ x =  \frac{2 \frac{ + }{ - }2 \sqrt{ - 3}  }{8}  \\ x =   \frac{1  \frac{ + }{ - }   \sqrt{3} i}{4} \:  \:  \:  \:  \:  \:  \: where \: i =  \: iota

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