Question

If (4x^2 - 3y^2) : (2x^2 + 5y^2) = 12:19, then, find x:y.

Answer 1

Heya...
Here is your answer ----


Q. (4x^2-3y^2) : (2x^2+5y^2) = 12:19

Solution.
=> 4x^2-3y^2 / 2x^2+5y^2 = 12/19
=> 19 (4x^2-3y^2) = 12 (2x^2+5y^2)
=> 76x^2 - 57y^2 = 24x^2 + 60y^2
=> 76x^2 - 24x^2 = 60y^2 + 57y^2
=> 52x^2 = 117y^2
=> x^2 = 117/52y^2
=> x^2/y^2 = 117/52 = 9/4
=> x/y = 3/2
=> x:y = 3:2

HOPE IT HELPS....!!

Answer 2

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