Math, asked by bbbb110041, 1 year ago

if 4x^2-6x-m is divisible by x-3 the value of m is

Answers

Answered by RonakMangal
1

Answer:

P(3)= 4(3)^2-6(3)-m

= 36-18-m=0

= -18+m

m= 18

Answered by super27
2

Answer:

Let (x-3) is a factor of 4x^2-6x-m

x-3=0

x=3

p(x) = 4x^2 -6x- m

p(3) = 4(3)^2 -6×3 -m

0= 4×9 - 18 -m

0= 36 -18 -m

0= 18 -m

m= 18

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