Question

if 4x^2+9y^2=136 and xy=10. find 2x+3y

Answer 1

hello users ....

we know that:
(a+b)² = a² + b² + 2ab

solution:-
given:
4x² + 9y² = 136
and
xy = 10

here,
we can write
4x² + 9y² = (2x)² + (3y)² = 136

now,
(2x + 3y)² = (2x)² + (3y)² + 2 × 2x × 3y

taking square root on both sides

=> (2x + 3y) = √ {(2x)² + (3y)² + 12xy }

=> (2x + 3y) = √ ( 136 + 12× 10)

=> (2x + 3y) = √ ( 136 + 120)

=> (2x + 3y) = √256

=> (2x + 3y) = 16 Answer

✴️⭐ hope it helps ⭐✴️

Answer 2

Answer:

16

Step-by-step explanation:

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