if 4x^2 + y^2 = 40 then find 2x+y
Attachments:
Answers
Answered by
3
(2x+y)^2=4x^2+y^2+4xy
putting the values given
(2x+y)^2=40+4(6)
(2x+y)^2=64
2x+y=√64
2x+y=8
putting the values given
(2x+y)^2=40+4(6)
(2x+y)^2=64
2x+y=√64
2x+y=8
Similar questions