If 4x+2y=16 and 6x-2y=4,find the value of y-x
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4x+2y=16
=>2(2x+y)=16
=>2x+y=8 ______i
6x-2y=4
=>2(3x-y)=4
=>3x-y=2 ______ii
Solving both i and ii
y=2x-8
substituting value of y in ii
3x-(2x-8)=2
=>3x-2x+8=2
=>x=2-8
=>x=-6
The value of x is -6
substituting value of x in i
2(-6)+y=8
=>-12+y=8
=>y=20
The value of y is 20
So the value of y-x is
20-(-6)
=20+6=26
Therefore the answer is 26
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