If 4x^3+7x^2-3x-6 find the quotation
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9^2x = 27^(3x-2)
To solve for x, we will use the exponent properties to find x.
First we will rewrite the bases as powers of prime numbers.
We know that:
9 = 3^2
27 = 3^3
Let us substitute.
==> 3^2)^2x = (3^3)^(3x-2)
Now we know that x^a^b = x^ab
==> 3^(2*2x) = 3^(3*(3x-2)
==> 3^(4x) = 3^(9x-6)
Now that the bases are equal, then the powers are equal too.
==> 4x = 9x -6
==> -5x = -6
==> x = 6/5
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