if 4x^3+8x^2-x-2=0 then value of 2x+3 is??
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Given: The polynomial 4x³ + 8x² - x - 2 = 0
To find: The value of 2x + 3 ?
Solution:
- Now we have given the equation as:
4x³ + 8x² - x - 2 = 0
- Taking common terms, we get:
4x²(x + 2) - 1(x + 2) = 0
(x + 2)(4x² - 1) = 0
(x + 2)(2x - 1)(2x + 1) = 0
- From this, the value of x is:
x = -2 , 1/2 and -1/2
- Putting this in 2x + 3, we get:
x = -2, we get:
2(-2)+3 = -4 + 3 = -1
x = 1/2, we get:
2(1/2) + 3 = 1 + 3 = 4
x = -1/2, we get:
2(-1/2) + 3 = - 1 + 3 = 2
Answer:
So the values of 2x + 3 are -1, 2 and 4.
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