Question

if 4x+3x = 4 and xy = 1/3 so, find the value of 64x³+ 27y³.​

Answer 1

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Answer 2

Step-by-step explanation:

taking equation 1

4x+3x=4

7x=4

x=4/7

taking equation 2 and putting the value of x

xy=1/3

4/7×y=1/3

y=1/3÷4/7

y=1/3×7/4

y=7/12

according to question

sorry I don't know how to write exponent

64x3+27y3

(64×4/7×4/7×4/7)+(27×7/12×7/12×7/12)

solve it your self