Question

If 4x + 3y = 10; xy = 2. Find 64 x^3 + 27 y^3​

Answer 1

Answer:

x=3 or x=1/2

Step-by-step explanation:

xy=2

y=2/x

4x+3y=10

4x+3(2/x)=10

$4 {x}^{2} + 6 = 10x$

$4 {x}^{2} - 10x - 6 = 0 \\ 4 {x}^{2} - 12x + 2x - 6 = 0 \\ 4x(x - 3) + 2(x - 3) = 0 \\ (x - 3)(4x - 2) = 0 \\ which \: means \: either \\ (x - 3) = 0 \: or(4x + 2) = 0 \\ this \: gives \: the \: solution \\ i.e.x = 3 \: or \: x = 1 \div 2$

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