if 4x - 3y = 4 and xy=1 , find the value of 4x+3y
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Answers
Answer:
8 and -8
Step-by-step explanation:
We first need to find the values of 'x' and 'y'
xy=1 or x=1/y
input x in 1st eq
4(1/y)-3y=4
Taking L.C.M
4/y-3y²/y=4
4-3y²=4y
0=3y²+4y-4
0=3y²+6y-2y-4
0=3y(y+2)-2(y+2)
0=(3y-2)(y+2)
So y=2/3 or y=-2
now use this value and find x
x=1/y or 3/2 or -1/2
now when x and y are 3/2 and 2/3
4(3/2)+3(2/3) = 6+2 = 8
now when x and y are -1/2 and -2
4(-1/2)+3(-2) = -2-6 = -8
Hope this helps.
xy=1
x=1/y
now x=1/y put in equation
4x1/y-3y=4
4/y-3y=4
both termes multiply by 'y'
4/y x y-3y x y=4xy
4-3y2=4y
4-3y2-4y=0
3y2-4y+4=0
3y2-6y+2y-4=0
3y(y-2)+2(y-2)=0
(y-2)(3y+2)=0
so, y=-2/3 or y=2
now case ( 1 )
x=2/y
y=-2/3 put in
x=2/-2/3
x=-3.33
now ,
4x+3y
put value's of x & y
4x-3.33+ 3 x-2/3
=-13.32-1.98
= -15.3
now case (2)
x=2/y
y=2 put in
x=2/2
x=1
put value's of x & y
4x+3y
=4x1+3x2
=4+6
=10