If 4x+3y/4x-3y =7/4 use the properties to find the value of 2x
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Step-by-step explanation:
Given If 4x+3y/4x-3y =7/4 use the properties to find the value of 2x^2 – 11y^2 / 2x^2 + 11y^2
- Given 4x + 3y / 4x – 3y = 7/4
- So we get by componendo and dividend,
- 4x + 3y + (4x – 3y) / 4x + 3y – (4x – 3y) = 7 + 4 / 7 – 4
- 8x / 6y = 11/3
- 4x/3y = 11/3
- So x/y = 11/3 x ¾
- Or x/y = 11/4
- Squaring both sides we get
- (x/y)^2 = (11/4)^2
- So x^2 / y^2 = 121 / 16
- Multiply 2/11 both sides
- 2/11 x^2 / y^2 = 121/16 x 2/11
- 2x^2 / 11y^2 = 11 / 8
2x^2 – 11y^2 / 2x^2 + 11y^2
= 11 – 8 / 11 + 8
= 3/19
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