If 4x + 3y = 72 & x + 3y = 36 ,then solution (x , y) is
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Answer:
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x = 4 and y= 3
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1
The solution (x, y) is (12, 8)
Given:
4x + 3y = 72 -----(1)
x + 3y = 36 -----(2)
To find:
Find the solution (x, y)
Solution:
To find x and y values by elimination method
Subtract (2) from (1)
⇒ 4x + 3y - (x + 3y ) = 72 - 36
⇒ 4x + 3y - x - 3y = 36
⇒ 3x = 36
⇒ x = 36/3 = 12
Now substitute x = 12 in (2)
(2) ⇒ 12 + 3y = 36
⇒ 3y = 24
⇒ y = 8
Therefore, the solution (x, y) = (12, 8)
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