Question

If 4x+3y=9andxy=2 find the value of 64xcube+27ycube

Answer 1

Answer:

675

Step-by-step explanation:

64x³ + 27y³

= (4x)³ + (3y)³

We know ,

a³ + b³ = (a+b)³-3ab(a+b)

Therefore ,

(4x + 3y)³ - 3×(4x×3y)(4x+3y)

= (9)³ - 3×2(9)

=729 - 54

=675

(Answer)