if 4x-5y = 12and xy = -1find 16x^2+25y^2
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1
Answer:
104
Step-by-step explanation:
You can refer the above figure.
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Given:-
☆Value of 4x-5y=12
☆Value of xy= -1
To find:-
☆Value of 16x²+25y²
Solution:-
By squaring both sides in the equation 4x-5y=12,we get:-
=>(4x-5y)²=(12)²
We know that (a-b)²=a²+b²-2ab
=>(4x)²+(5y)²-2×4x×5y=144
=>16x²+25y²-40xy=144
=>16x²+25y²-40(-1)=144
=>16x²+25y²+40=144
=>16x²+25y²=144-40
=>16x²+25y²=104
Thus,value of 16x²+25y² is 104.
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