Question

if 4x+5y=82, 3x+2z=54 and 5y+4z=110 then 5x+2y+z=


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Answer 1

Answer:

75

Step-by-step explanation:

from 1st equation

4x = 82 - 5y

x = 82/4 - 5y/4

by substituting it in second

3(82/4 - 5y/4) +2z = 54

246/4 - 15y/4 +2z = 54

2z = 54 - 246/4 + 15y/4

z = 27 - 123/4 + 15y/8

by substituting it in third

5y + 4( 27 - 123/4 + 15y/8)=110

5y + 108 - 123 + 15y/2 = 110

25y/2 = 125

y = 125*2/25 = 10

y=10

by substituting this in first and third

4x + 5*10 = 82

4x= 82-50=32

x= 8

5*10+4z=110

4z= 110-50 =60

z= 15

5x+ 2y + z = 5*8 +2*10 + 15 = 75

Answer 2

• Step-by-step explation