Question

if 4x=81/x then what is the value of x?
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Answer 1

Step-by-step explanation:

4x=81x

x^2=81/4

x=9/2

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Answer 2

Step-by-step explanation:

$4x = \frac{81}{x}$

$= > 4 {x}^{2} = 81$

$(2x) ^{2} = {9}^{2}$

$(2x) ^{2} - {9}^{2} = 0$

$= > (2x - 9)(2x + 9) = 0$

therefore x=9/2 or -9/2