If 4x=cosec theta and 8/x=cot theta ,then find the value of 4(x square -1/x square)
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Answer:
1/4
Step-by-step explanation:
Given 4x=cosec theta and 8/x=cot theta,
there is a mistake 4/x=cot theta,
Now consider , 4(x² - 1/x²)
=4(x-1/x)(x+1/x)
We have x = cosec∅/4
1/x = cot∅/4
=> (x + 1/x) = 1/4(cosec∅ + cot∅)
=>(x - 1/x) = 1/4 (cosec∅ - cot∅)
=>4(x + 1/x)(x - 1/x)
= 4*1/4((cosec∅ + cot∅)*1/4* (cosec∅ - cot∅)
=1/4(cosec²∅ - cot²∅)
=1/4 (Since cosec²∅ - cot²∅ = 1)
=1/4.----Ans
kunaldahiya92701:
But in my question in statement their 8 but in find out their is 4 so my answer is 1/16 please find is it write or wrong
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