If 4x+i(3x-y)=3+i(-6) where x and y are real numbers then find the values of x and y
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Given;4x+i(3x-y)=3+i(-6)
To Find; values of x and y
Solution; 4x+i(3x-y)=3+i(-6)
Comparing The complex and real part
4x=3
x=3/4
3x-y=-6
9/4-y=-6
y=8.25
Hence the value of x and y are 3/4 and 8.25 respectively
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