Math, asked by hyinterbuilt5471, 1 year ago

If 4x+i(3x-y)=3+i(-6) where x and y are real numbers then find the values of x and y

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Answered by preethiganghatharan
26

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Answered by halamadrid
1

Given;4x+i(3x-y)=3+i(-6)

To Find; values of x and y

Solution; 4x+i(3x-y)=3+i(-6)

Comparing The complex and real part

4x=3

x=3/4

3x-y=-6

9/4-y=-6

y=8.25

Hence the value of x and y are 3/4 and 8.25 respectively

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