if 4x is equal to secant theta and 4 by x is equal to tan theta then the value of 8 into x square minus one by x square
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Hi ,
Given
here I am taking A instead of theta ,
4x = sec A --- ( 1 )
4/x= tan A -----( 2 )
we know the trigonometric identity
sec² A - tan² A = 1
( 4x )² - ( 4/x )² = 1 from ( 1 ) and ( 2 ),
16x² - 16 / x² = 1
16( x² - 1/x² ) = 1
2× 8 ( x² - 1 / x² ) = 1
Therefore ,
8( x² - 1 / x² ) = 1/2
I hope this helps you.
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