Question

If 4x=Sec 0 and 4/x = tan 0,then the value of 8 (x square 1/x square) is ​

Answer 1

Answer:

1

Step-by-step explanation:

$4x = sec \: theta \\ \frac{4}{x} = tan \: theta$

we know ,

$sec {}^{2} theta \: - tan {}^{2} theta \: = 1$

so,

${(4x)}^{2} - { (\frac{4}{x} )}^{2} = 1$

$8 {x}^{2} - \frac{8}{ {x}^{2} } = 1$

Now, taking 8 as common

$8( {x}^{2} - { (\frac{1}{x} )}^{2} ) = 1$

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Answer 2

Answer:

Sect =4x.

So answer is 56

Step-by-step explanation: