Question

if 4x, x+20, 5x-9 are in an AP find the value if x​

Answer 1

Answer:

if 4x, x+20, 5x-9 are in an AP then

x+20-4x = 5x-9-x-20

7x = 49

x = 7 Ans.

Answer 2

$\huge\mathfrak\purple{★SolutioN : }$

Given that,

If 4x, x+20, 5x-9 are in an AP find the value if x.

Let,

• a1 = 4x
• a2 = x + 20
• a3 = 5x - 9

We know that, the common difference of an AP terms are equal. So,

↪ a2 - a1 = a3 - a2

➡ (x + 20) - (4x) = (5x - 9) - (x + 20)

➡ x + 20 - 4x = 5x - 9 - x - 20

➡ 20 - 3x = 4x - 29

➡ 20 + 29 = 4x + 3x

➡ 7x = 49

➡ x = 49/7

➡ x = 7

$\boxed{∴ \: x = 7}$

Step-by-step explanation:

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