Question

if (4x²+1)(2x+1)(2x-1) = 4095. Find (x²+3)(x+2)(x-2)?​

Answer 1

Step-by-step explanation:

(4x2+1)(2x+1)(2x-1)

=(4x^2+1)(4x^2-1) as (2x+1)(2x-1)=4×^2-1

= 16x^2-1=4095

=16x^2=4096

x^2=256

x=16

(×^2+3)(×+2)(×-2) = (×^2+3)(×^2-4)

= (256+3)(256-4)

=259×252

=65268

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