Question

If 4x²+25y²=41 and xy=2 then find 2x-5y

Answer 1

(2x)^2+(5y)^2+2×2x×5y = 41 +2×2x×5y

(2x+5y)^2= 41+20xy

(2x+5y)^2= 41+20×2


(2x+5y)^2=81

2x+5y = 9


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