If ( 4x2 + 4x + 1) is divided by ( 2x + 1), the remainder is
Fa) (2x + 1)
b) (2x - 1)
c) 2x
d) o
an
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4x^2 + 4x +1
Can be written as
(2x)^2 + 2.(2x).(1) + (1)^2
This is in form
a^2 + 2.a.b + b^2 = (a+b)^2
=====> (2x+1)^2
=====> (2x+1).(2x+1)
Divide this by 2x+1 you’ll be remaining with 2x+1 as remainder
Answer —-> (a)
Can be written as
(2x)^2 + 2.(2x).(1) + (1)^2
This is in form
a^2 + 2.a.b + b^2 = (a+b)^2
=====> (2x+1)^2
=====> (2x+1).(2x+1)
Divide this by 2x+1 you’ll be remaining with 2x+1 as remainder
Answer —-> (a)
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