if 4x²+y²=40 and xy=6 find value 2x+y
Answers
Answered by
15
Hi Friend,
We know that,
__________________
( a + b )² = a² + 2ab + b²
___________________
According to the problem given,
4x² + y² = 40-------( 1 )
xy = 6----------------( 2 )
Do the square of ( 2x + y ),
( 2x + y )² = ( 2x )² + 2 × 2x×y + y²
= 4x² + 4xy + y²
= 4x² + y² + 4xy
= 40 + 4 × 6
[ from ( 1 ) and ( 2 ) ]
( 2x + y )² = 40 + 24
= 64
Therefore ,
2x + y = ±√64
= ± 8
I hope this helps you.
We know that,
__________________
( a + b )² = a² + 2ab + b²
___________________
According to the problem given,
4x² + y² = 40-------( 1 )
xy = 6----------------( 2 )
Do the square of ( 2x + y ),
( 2x + y )² = ( 2x )² + 2 × 2x×y + y²
= 4x² + 4xy + y²
= 4x² + y² + 4xy
= 40 + 4 × 6
[ from ( 1 ) and ( 2 ) ]
( 2x + y )² = 40 + 24
= 64
Therefore ,
2x + y = ±√64
= ± 8
I hope this helps you.
kajalsinghal:
thank you frie
Answered by
15
Topic: Algebraic Identities
Question:
If 4x² +y ² = 40 and xy = 6 find value 2x + y.
Solution:
➠( 2x + y )² ➙ ( 2x)² + y² + 2 × 2x × y
➠( 2x + y )² ➙ ( 4x² + y² ) + 4xy
➠( 2x + y )² ➙ 40 + 4 × 6 [Using 4x²+y²➛40 and xy➛6]
➠( 2x + y )² ➙ 64
➠2x + y ➙ (+ 8)²
➠2x + y ➙ + 8
Identity Used:
( a + b )² ➝ a² + 2ab + b²
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