Question

if 4x²+y²=40 and xy=6then the value of 2x+y
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Answer 1

bro

please see to to the attachment

Answer 2

The value of 2x+y is ±8.

Step-by-step explanation:

$4x^{2} +y^{2} =40$

$xy=6$

we have to find the value of $2x+y$.

$(2x+y)^{2} =4x^{2} +y^{2} +2.2x.y$

⇒$(2x+y)^{2}=4x^{2} +y^{2} +4xy$

⇒$(2x+y)^{2}=(4x^{2} +y^{2} )+4(xy)$

putting the values,

⇒$(2x+y)^{2}=40+4*6$

⇒$(2x+y)^{2}=64$

⇒$(2x+y)=$±$8$