if 4x²+ y² equal to 40 and xy is equal to 6 find the value of 2x+y
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Using identity (a + b)^2 = a^2 + b^2 + 2ab
(2x + y)^2 = (4x^2 + y^2) + (4xy)
by substituting the given values we get,
(2x + y)^2 = 40 + 4*6
(2x + y)^2 = 64
2x + y = 8
(2x + y)^2 = (4x^2 + y^2) + (4xy)
by substituting the given values we get,
(2x + y)^2 = 40 + 4*6
(2x + y)^2 = 64
2x + y = 8
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