if 4xsquare - 6x-k is exactly divisible by x-3 then k
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Answered by
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x-3=0
x=3
Put x=3 in 4x²-6x-k
4x²-6x-k=0
4(3)²-6(3)-k=0
4(9)-18-k=0
36-18=k
k=18
x=3
Put x=3 in 4x²-6x-k
4x²-6x-k=0
4(3)²-6(3)-k=0
4(9)-18-k=0
36-18=k
k=18
lucky432:
tqs
Answered by
0
Hey user here is your answer....
________________________________
◆Given expression- 4x^2-6x-k
◆x-3=0
◆x=3
◆Put in given equation
◆4(3)^2-6(3)-k=0
◆36-18-k=0
◆18-k=0
◆k=18
__:___________________________
⭐️Hope it helps you⭐️
✌️Rohan ( Maths aryabhatta)✌️
________________________________
◆Given expression- 4x^2-6x-k
◆x-3=0
◆x=3
◆Put in given equation
◆4(3)^2-6(3)-k=0
◆36-18-k=0
◆18-k=0
◆k=18
__:___________________________
⭐️Hope it helps you⭐️
✌️Rohan ( Maths aryabhatta)✌️
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