Question

If 4xy7 is exactly divisible by 3,then the least value of (x+y)math​

Answer 1

Answer:

1

Step-by-step explanation:

4+7=11

12 is one greater than 11 and divisible by 3

so ans is 1

Answer 2

For a number to be divisible by 3 ,the sum of its digits must be divisible by 3 then total number of divisible by 3

SO, GIVEN ,

Number = 4xy7

==>According to Above statement

4+x+y+7= a number which is divisible by 3

=11+x+y

multiple of 3 are 3,6,9,12...............

We take ,x+y+11=12

Therefore

$x + y = 1$

Hope it helps.......!!!!!!!!!

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