If 4y - 1/4y = 2, find the value of 16y^2 + 1/16y^2
Answers
Answered by
5
Step-by-step explanation:
(16y
2
−1)+(1−4y)
2
=16y
2
−1+1+16y
2
−8y
=32y
2
−8y
=8y(4y−1)
So, 8y is a factor.
Hence, D is correct option.
Answered by
0
Answer:
4y- ¼y=2
4y-4y=2
y=2
then :
16y²+1/16y²
16(2)²+1/16(2)²
16×4+1/16×4
64+4/16. (make it simplified )
64+2/8
64+1/4
68. is the answer
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