If 4y I 9 greater than the sum of y, and 3x, by how much is y greater than x
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4y - 9 > y + 3x; 4y - y > 3x + 9
3y > 3(x + 3); y = > \(\frac{3(x + 3)}{3}\)y > x + 3; y - 3 > x
y is greater than x
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