if √5 +√10+√15+...√100 =a+b√5 than the valu of a and b
Answers
Answered by
1
Answer:
The sum of 5+10+15 ….+100 is the sum of an AP whose first terms is 5, the last term is 100 and the common difference is 5.
Th = 100 = a +(n-1)d = 5 +(n-1)5 = 5
Sn = (n/2)[2a+(n-1)d]
= (20/2)[2*5+ (20–1)*5]
= 10[10+95]
= 10*105
= 1050
Similar questions