Physics, asked by vignesh736, 10 months ago

If 5×10^19 electron flows through the conductor is 4S. Then the current is (e= 1.6×10^-19)

Answers

Answered by pal69

1

Answer:

q=it

ne=it

i=ne/t=5×10^19×1.6×10^-19/4=2A

I=2A

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