IF(5,2)(-3,4) (X,Y) ARE COLLINEAR SHOW THAT X +4Y-13=0
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if they are collinear the area will be 0
take x1=5 y1 =2 x2=-3 y2=4 x3=x y3=y
x1(y2-y3)+x2(y3-y1)+x3(y1-y2) = 0
5(4-y)+(_3)(y-2)+x(2-4)=0
20-5y-3y+6-2x=0
-2x-8y+26=0
-2(x+4y-13)=0
x+4y-13=0
take x1=5 y1 =2 x2=-3 y2=4 x3=x y3=y
x1(y2-y3)+x2(y3-y1)+x3(y1-y2) = 0
5(4-y)+(_3)(y-2)+x(2-4)=0
20-5y-3y+6-2x=0
-2x-8y+26=0
-2(x+4y-13)=0
x+4y-13=0
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