Math, asked by uchaidipak, 7 months ago

If (5,2) is a solution of the equation kx+4Y=33, find the value of k​

Answers

Answered by sainsunil121
7

Answer:

5

Step-by-step explanation:

k×5+4×2=33

5k=33-8

k=25/5

k=5

Answered by tennetiraj86
20

Answer:

\huge{\boxed{\rm{\red{K=5}}}}

Step-by-step explanation:

Given equation is Kx+4y=33

Given point is (5,2)

If (5,2) is a solution of the given equation then it satisfies the given equation .

Put x=5 and y=2 then

=>k(5)+4(2)=33

=>5k+8=33

=>5k=33-8

=>5k=25

=>k=25/5

=>k=5

The value of k is 5

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