Math, asked by radhikapatel281081, 17 days ago

if (5,2) is a solution of the equation kx+4y33 find the value of k​

Answers

Answered by deshmukhgauri173
3

answer=5

Step-by-step explanation:

Given equation is Kx+4y=33

Given point is (5,2)

If (5,2) is a solution of the given equation then it satisfies the given equation .

Put x=5 and y=2 then

=>k(5)+4(2)=33

=>5k+8=33

=>5k=33-8

=>5k=25

=>k=25/5

=>k=5

The value of k is 5

Answered by sadiafaisal
0

Answer:

-52.8

Step-by-step explanation:

kx + 4y33

5k + 4 (2)(33)=0

5k + 264=0

5k = -264

k = -264/5

k = -52.8

Similar questions